Which of the following represent represent clear electropositive properties

Options

A. F
B. Cl
C. Br
D. l

Answer

To determine which of the given elements (Fluorine, Chlorine, Bromine, or Iodine) represents clear electropositive properties, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Elements**: The elements in question are Fluorine (F), Chlorine (Cl), Bromine (Br), and Iodine (I). All of these elements belong to the halogen group in the periodic table.

2. **Understand Electronegativity**: Electronegativity is a measure of the tendency of an atom to attract a bonding pair of electrons. In the context of the halogens, as we move down the group from Fluorine to Iodine, the electronegativity decreases.

3. **Rank the Electronegativity**:
- Fluorine is the most electronegative element in the periodic table.
- Chlorine is less electronegative than Fluorine.
- Bromine is less electronegative than Chlorine.
- Iodine is the least electronegative among these four elements.

4. **Relate Electronegativity to Electropositivity**: Electropositivity refers to the tendency of an atom to lose electrons and form positive ions. As electronegativity decreases, electropositivity increases. Therefore, the element with the lowest electronegativity will exhibit the most electropositive character.

5. **Conclusion**: Since Iodine has the lowest electronegativity among the given options, it will exhibit the clearest electropositive properties. Thus, the correct answer is Iodine (I).

### Final Answer:
The element that represents clear electropositive properties is **Iodine (I)**.

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