The more activeness of fluorine is due to

Options

A. F-F bond has less energy
B. `F_(2)` is gas it normal temperature
C. Its electron affinity is maximum
D. F-F bond has more energy

Answer

**Step-by-Step Solution:**

1. **Understanding Fluorine's Reactivity**: Fluorine is known for its high reactivity among the halogens. To understand why, we need to analyze its properties, particularly its bond strength and electronegativity.

2. **Fluorine-Fluorine Bond**: The diatomic molecule of fluorine (F2) has a fluorine-fluorine bond. This bond is relatively weak due to the small size of the fluorine atoms. The small atomic radius leads to significant inter-electronic repulsion between the non-bonding electrons of the two fluorine atoms.

3. **Bond Energy**: The bond energy of the F2 molecule is low. This means that less energy is required to break the bond between the two fluorine atoms. Consequently, the F2 molecule can easily dissociate into two fluorine atoms, making it reactive.

4. **Electronegativity**: Fluorine is the most electronegative element in the periodic table. Its high electronegativity means that it has a strong tendency to attract electrons from other elements during chemical reactions, further enhancing its reactivity.

5. **Oxidizing Power**: Fluorine has a high oxidizing power, which means it can readily gain electrons from other substances. This characteristic is a direct result of its high electronegativity and contributes to its overall reactivity.

6. **Conclusion**: The more activeness of fluorine is primarily due to the weak fluorine-fluorine bond, which has low energy, allowing it to break easily. Additionally, its high electronegativity and oxidizing power also play significant roles in its reactivity.

**Final Answer**: The more activeness of fluorine is due to the weak fluorine-fluorine bond which has low energy.

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