`HgCl_(2)` and `I_(2)` both when dissolved in water containing `I^(-)` ions the pair of species formed is:

Options

A. `HgI_(2),I^(-)`
B. `HgI_(4)^(2-),I_(3)^(-)`
C. `Hg_(2)I_(2),I^(-)`
D. `HgI_(2),I_(3)^(-)`

Answer

B

Explanation

`HgCl_(2) + 2I^(-) to underset([HgI_(4)]^(-2))underset(darr +2I^(-))(HgI_(2)) + 2Cl^(-)`
Soluble complex
`I_(2) +I^(-) to I_(3)^(-) ` water