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Which is insoluble in water...

Which is insoluble in water

A

`H_(2)S`

B

`HgCl_(2)`

C

`Ca(NO_(3))_(2)`

D

`CaF_(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which compound is insoluble in water, we need to analyze the solubility of the given compounds based on their polarity and lattice energy. Here’s a step-by-step solution: ### Step 1: Understand Polarity - Water (H2O) is a polar solvent. For a compound to be soluble in water, it generally needs to be polar as well. ### Step 2: Analyze H2S - Hydrogen sulfide (H2S) is slightly polar. - It is known to be slightly soluble in water due to its polarity, but not highly soluble. ### Step 3: Analyze HgCl2 - Mercury(II) chloride (HgCl2) is also polar. - It is soluble in water, which means it can interact favorably with water molecules. ### Step 4: Analyze CaF2 - Calcium fluoride (CaF2) is an ionic compound. - It has a very high lattice energy due to the strong electrostatic forces between the calcium ions (Ca²⁺) and fluoride ions (F⁻). ### Step 5: Lattice Energy Consideration - Compounds with high lattice energy are generally less soluble in water. - The high lattice energy of CaF2 means that it is not easily dissociated in water, leading to its insolubility. ### Conclusion - Based on the analysis, the compound that is insoluble in water is **CaF2** (Calcium fluoride).

To determine which compound is insoluble in water, we need to analyze the solubility of the given compounds based on their polarity and lattice energy. Here’s a step-by-step solution: ### Step 1: Understand Polarity - Water (H2O) is a polar solvent. For a compound to be soluble in water, it generally needs to be polar as well. ### Step 2: Analyze H2S - Hydrogen sulfide (H2S) is slightly polar. - It is known to be slightly soluble in water due to its polarity, but not highly soluble. ...
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