Which of the following is most easily hydrolysed amongst the following

Options

A. `SF_(6)`
B. `NF_(3)`
C. `C Cl_(4)`
D. `TeF_(6)`

Explanation

To determine which of the given compounds is most easily hydrolyzed, we will analyze each compound based on its structure and stability.

### Step-by-Step Solution:

1. **Identify the Compounds**: The compounds given are SF6 (sulfur hexafluoride), NF3 (nitrogen trifluoride), CCl4 (carbon tetrachloride), and TeF6 (tellurium hexafluoride).

2. **Understand Hydrolysis**: Hydrolysis refers to the reaction of a compound with water, leading to the breakdown of that compound. The ease of hydrolysis often depends on the stability of the compound and the nature of the bonds present.

3. **Analyze SF6**:
- SF6 is a stable compound due to the strong S-F bonds.
- The size of sulfur is larger compared to fluorine, which leads to a stable octet configuration.
- Hydrolysis of SF6 is not easy due to its stability.

4. **Analyze NF3**:
- NF3 is also stable due to strong N-F bonds.
- The nitrogen atom is small and does not have vacant d-orbitals to accommodate additional interactions.
- Therefore, NF3 cannot be easily hydrolyzed.

5. **Analyze CCl4**:
- CCl4 is stable because of the strong C-Cl bonds.
- Carbon does not have vacant d-orbitals, and the compound is non-polar.
- Hydrolysis of CCl4 is not feasible due to its stability.

6. **Analyze TeF6**:
- TeF6 is less stable compared to the other compounds.
- Tellurium has vacant d-orbitals that can accommodate interactions with water.
- The presence of a larger central atom (Te) and the small size of F- leads to instability, making hydrolysis easier.

7. **Conclusion**: Among the given compounds, TeF6 is the most easily hydrolyzed due to its instability and the ability of tellurium to interact with water.

### Final Answer:
**TeF6 is the compound that is most easily hydrolyzed among the given options.**

---