What is the product obtained when `MnO_(2)` solution is boiled with `PbO_(2)` and concentrated `HNO_(3)`

Options

A. `MnO_(2)`
B. `HMnO_(4)`
C. `Mn_(3)O_(4)`
D. `PbMnO_(4)`

Explanation

To determine the product obtained when MnO₂ solution is boiled with PbO₂ and concentrated HNO₃, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- We have manganese dioxide (MnO₂), lead dioxide (PbO₂), and concentrated nitric acid (HNO₃).

2. **Understand the Reaction**:
- When MnO₂ is treated with PbO₂ and concentrated HNO₃, a redox reaction occurs. In this reaction, MnO₂ acts as a reducing agent, while PbO₂ acts as an oxidizing agent.

3. **Write the Balanced Chemical Equation**:
- The balanced equation for the reaction is:
\[ 2 \text{MnO}_2 + 5 \text{PbO}_2 + 6 \text{HNO}_3 \rightarrow 2 \text{HMnO}_4 + 5 \text{Pb(NO}_3)_2 + 2 \text{H}_2\text{O} \]
- This equation shows that manganese dioxide is converted into permanganic acid (HMnO₄), while lead dioxide is converted into lead nitrate (Pb(NO₃)₂).

4. **Identify the Main Product**:
- From the balanced equation, we can see that the main product formed is permanganic acid (HMnO₄).

5. **Select the Correct Answer**:
- Given the options:
1. MnO₂
2. HMnO₄
3. MnO₃
4. PbMnO₄
- The correct answer is option 2: HMnO₄.

### Final Answer:
The product obtained when MnO₂ solution is boiled with PbO₂ and concentrated HNO₃ is **HMnO₄**.

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