The oxide which gives hydrogen peroxide on treatment with dilute acid is

Options

A. `PbO_(2)`
B. `Na_(2)O_(2)`
C. `MnO_(2)`
D. `TiO_(2)`

Explanation

To solve the question, we need to identify which oxide produces hydrogen peroxide (H2O2) when treated with a dilute acid. Let's analyze the options provided: PbO2, Na2O2, MnO2, and TiO2.

### Step-by-Step Solution:

1. **Identify the Oxides**:
- The given oxides are PbO2 (Lead(IV) oxide), Na2O2 (Sodium peroxide), MnO2 (Manganese(IV) oxide), and TiO2 (Titanium(IV) oxide).

2. **Understand the Reaction with Dilute Acid**:
- We need to find out which of these oxides reacts with a dilute acid to produce hydrogen peroxide (H2O2).

3. **Analyze Each Oxide**:
- **PbO2**: When treated with dilute acid, it generally forms lead salts but does not produce H2O2.
- **Na2O2**: Sodium peroxide reacts with dilute sulfuric acid (H2SO4) to produce sodium sulfate (Na2SO4) and hydrogen peroxide (H2O2).
\[ \text{Na}_2\text{O}_2 + \text{H}_2\text{SO}_4 \rightarrow \text{Na}_2\text{SO}_4 + \text{H}_2\text{O}_2 \]
- **MnO2**: Manganese dioxide does not produce H2O2 when treated with dilute acid.
- **TiO2**: Titanium dioxide does not yield hydrogen peroxide with dilute acids.

4. **Conclusion**:
- The oxide that gives hydrogen peroxide when treated with dilute acid is **Na2O2 (Sodium peroxide)**.

### Final Answer:
The oxide which gives hydrogen peroxide on treatment with dilute acid is **Na2O2 (Sodium peroxide)**.

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