Which of the following is ionic

Options

A. `AgF`
B. `AgCl`
C. `AgBr`
D. `AgI`

Explanation

To determine which of the given compounds is ionic, we need to analyze the nature of the bonds formed in each compound. The options provided are: AgF, AgCl, AgBr, and AgI.

### Step-by-Step Solution:

1. **Identify the Compounds:**
- The compounds given are silver fluoride (AgF), silver chloride (AgCl), silver bromide (AgBr), and silver iodide (AgI).

2. **Understand Ionic vs. Covalent Bonds:**
- Ionic bonds are formed between metals and non-metals where there is a transfer of electrons. This typically occurs when there is a significant difference in electronegativity between the two atoms involved.
- Covalent bonds are formed when two non-metals share electrons.

3. **Analyze Each Compound:**
- **AgF (Silver Fluoride):**
- Fluorine is highly electronegative and has a small atomic size, which allows for a strong ionic bond with silver.
- **AgCl (Silver Chloride):**
- Chlorine is also electronegative but less so than fluorine. The bond is primarily ionic but has some covalent character.
- **AgBr (Silver Bromide):**
- Bromine is less electronegative than chlorine, leading to a bond that is more covalent than ionic.
- **AgI (Silver Iodide):**
- Iodine is even less electronegative than bromine, resulting in a bond that is predominantly covalent.

4. **Determine the Ionic Compound:**
- Among the compounds analyzed, AgF stands out as the most ionic due to the small size and high electronegativity of fluorine, which allows for a strong ionic bond with silver.

5. **Conclusion:**
- Therefore, the ionic compound among the options is **AgF**.

### Final Answer:
**AgF is the ionic compound.**