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The oxidation number of Cr in the produc...

The oxidation number of Cr in the product of alkaline oxidative fusion of `FeCr_2O_4` is

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The correct Answer is:
6
`4FeCr_(2)O_(4)+16NaOH+7O_(2)rarr8Na_(2)CrO_(4)+2Fe_(2)O_(3)+8H_(2)O`
Let the oxidation state of `Cr` in `CrO_(4)^(2-)` is x .
So `x+4(-2)=-2" or "x=6`
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