An organic compound 'A' burns with a sooty flame. It is negative towards Tollen's reagent test and positive for Borsche's reagent test. The compound 'A' is

Options

A. Benzaldehyde
B. Acetophenone
C. Acetone
D. Salicylic's acid

Answer

To determine the organic compound 'A', let's analyze the information given step by step.

### Step 1: Analyze the Flame Test
The question states that the organic compound 'A' burns with a sooty flame.
- **Interpretation**: A sooty flame indicates that the compound is likely aromatic. Aromatic compounds tend to have a higher carbon content and produce soot when burned due to incomplete combustion.

**Hint**: Remember that aromatic compounds typically burn with a sooty flame due to their structure.

### Step 2: Tollen's Reagent Test
The compound 'A' is negative towards Tollen's reagent test.
- **Interpretation**: Tollen's reagent is used to test for aldehydes, which reduce the reagent and produce a silver mirror. A negative result indicates that 'A' is not an aldehyde.

**Hint**: Tollen's reagent is specific for aldehydes; a negative result suggests that the compound is not an aldehyde.

### Step 3: Borsche's Reagent Test
The compound 'A' is positive for Borsche's reagent test.
- **Interpretation**: Borsche's reagent is used to test for ketones. A positive result indicates that 'A' is a ketone.

**Hint**: Borsche's reagent is a test specifically for ketones; a positive result confirms the presence of a ketone functional group.

### Step 4: Conclusion
From the above analysis:
- The compound 'A' is aromatic (sooty flame).
- It is not an aldehyde (negative Tollen's test).
- It is a ketone (positive Borsche's test).

Given these characteristics, the most likely candidate for compound 'A' is **acetophenone**, which is an aromatic ketone.

**Final Answer**: The compound 'A' is acetophenone.