Glucose forms many derivatives. The derivative which will help to prove the furanose structure is

Options

A. Acetyl
B. Benzoyl
C. Osazone
D. Isopropylidene

Explanation

To determine which derivative of glucose helps to prove the furanose structure, we can follow these steps:

### Step 1: Understand the Structure of Glucose
Glucose is a six-carbon sugar (hexose) that can exist in two cyclic forms: the pyranose form (six-membered ring) and the furanose form (five-membered ring).

### Step 2: Identify Derivatives of Glucose
Glucose can form various derivatives, including acetone, benzoin, isopropylidene, and others. Each derivative has different structural characteristics.

### Step 3: Analyze the Derivatives
- **Acetone**: This is a simple ketone and does not provide information about the structure of glucose.
- **Benzoin**: This is an aromatic compound and does not relate to the cyclic structure of glucose.
- **Isopropylidene**: This derivative is formed by protecting the hydroxyl groups of glucose. It requires the presence of two adjacent free OH groups, which is characteristic of the furanose form.
- **Osa-jun**: This is not a recognized derivative of glucose.

### Step 4: Conclusion
The derivative that helps to prove the furanose structure of glucose is **isopropylidene**. This is because the formation of this derivative requires the specific orientation of the hydroxyl groups that is only found in the furanose form of glucose.

### Final Answer
The derivative which will help to prove the furanose structure is **isopropylidene**.

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