The products expected from the reaction
`{:(CHO),("|"),(CH_(2)),("|"),(CHOH),("|"),(CHOH),("|"),(CH_(2)OH):} overset(HIO_(4))underset("excess")to`

Options

A. `H-overset(O)overset(||)(C)-CH_(2)-CHO +HCOOH+HCHO`
B. HOOC-CHOH-CHOH-COOH+HCOOH
C. `HOOC-CH_(2)CH_(2)COOH+HCOOH+HCHO`
D. `HOOC-COOH+HCOOH+HCHO`

Explanation

To solve the question regarding the products expected from the reaction of the given compound with excess HIO4, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Structure**: The compound given is a polyol (a molecule with multiple hydroxyl groups). It has several functional groups including aldehydes and alcohols.

2. **Understand the Reagent**: HIO4 (periodic acid) is known to cleave vicinal diols (1,2-diols) and can oxidize aldehydes. When it reacts with polyols, it typically breaks the carbon-carbon bonds between hydroxyl groups and can oxidize the resulting aldehydes.

3. **Reaction Mechanism**: When the polyol reacts with excess HIO4, the hydroxyl groups are oxidized and the carbon chains are cleaved. This results in the formation of smaller aldehyde and carboxylic acid products.

4. **Predict the Products**:
- The reaction will yield formic acid (HCOOH) from the oxidation of the terminal aldehyde.
- It will also produce formaldehyde (HCHO) from the oxidation of the adjacent aldehyde.
- The remaining carbon chain will yield another aldehyde, specifically, it will produce malonaldehyde (which is a 3-carbon chain with two aldehyde groups).

5. **Summarize the Products**: The expected products from the reaction are:
- Malonaldehyde (CH2(CHO)2)
- Formic acid (HCOOH)
- Formaldehyde (HCHO)

### Final Answer:
The products expected from the reaction of the given compound with excess HIO4 are malonaldehyde, formic acid, and formaldehyde.

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