At `300 K`, `36 g` of glucose present per litre in its solution has an osmotic pressure of `4.98 bar`. If the osmotic pressure of the solution is `1.52 bar` at the same temperature, what would be its concentration?

Explanation

`pi=CRT" (C = molar concentration)"`
`(pi_(1))/(pi_(2))=(C_(1))/(C_(2))," "(4.98)/(1.52)=(36//180)/(C_(2))" or "C_(2)=(36)/(180)xx(1.52)/(4.98)="0.061 M"`