Determine the osmotic pressure of a solution prepared by dissolving `"25 mg of "K_(2)SO_(4)` in 2 litre of water at `25^(@)C`, assuming that it is completely dissociated.

Explanation

`K_(2)SO_(4)" dissolved = 25 mg = 0.025 g"`
`"Molar mass of "K_(2)SO_(4)=2xx39+32+4xx16="174 g mol"^(-1)`
As `K_(2)SO_(4)` dissociates completely as `K_(2)SO_(4)rarr 2K^(+)+SO_(4)^(2-)`, i.e., ions produced = 3, `therefore i=3`
`thereforepi=iCRT=i(n)/(V)RT=ixx(w)/(M)xx(1)/(V)RT=3xx("0.025 g")/("174 g mol"^(-1))xx(1)/(2K)xx"0.0821 L atm K"^(-1)"mol"^(-1)xx"298 K"`
`=5.27xx10^(-3)" atm."`