The rate of a particular reaction doubles when temperature changes from `27^(@)` C to `37^(@)C`. Calculate the energy of activation of such a reaction.

Explanation

To calculate the activation energy (Ea) for the reaction where the rate doubles when the temperature changes from 27°C to 37°C, we can use the Arrhenius equation and the relationship between the rate constants at two different temperatures.

### Step-by-Step Solution:

1. **Convert temperatures from Celsius to Kelvin:**
- \( T_1 = 27°C + 273 = 300 \, K \)
- \( T_2 = 37°C + 273 = 310 \, K \)

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