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The factor e^(-E//RT) in Arrhenius equat...

The factor `e^(-E//RT)` in Arrhenius equation is called…………………….factor.

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Boltzmann
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The rate of chemical reaction are strongly affected by temperature . Arrhenius (1889) gave following relation between rate contant and temperature . k=Ae^(-E_(a)//RT)" ".....(i) This equation is called Arrhenius equation. The constant 'A' is caleld Arrhenius of pre-exponential factor. Logarithm of equation (i) given : log_(10)k=log_(10)A(E_(a))/(2.3030RT)" ".....(ii) The rate constant for a reaction is . log_(10)"sec"^(-1)=14-(1.25xx10^(4)K)/(T) " ".....(iii) The pre-exponential factor or frequency factor of the reaction under consideration is :

The rate of chemical reaction are strongly affected by temperature . Arrhenius (1889) gave following relation between rate contant and temperature . k=Ae^(-E_(a)//RT)" ".....(i) This equation is called Arrhenius equation. The constant 'A' is caleld Arrhenius of pre-exponential factor. Logarithm of equation (i) given : log_(10)k=log_(10)A(E_(a))/(2.3030RT)" ".....(ii) The rate constant for a reaction is . log_(10)"sec"^(-1)=14-(1.25xx10^(4)K)/(T) " ".....(iii) At what temperature, rate constant of the reaction is equal to the pre-exponenntial factor ?

The rate of chemical reaction are strongly affected by temperature . Arrhenius (1889) gave following relation between rate contant and temperature . k=Ae^(-E_(a)//RT)" ".....(i) This equation is called Arrhenius equation. The constant 'A' is caleld Arrhenius of pre-exponential factor. Logarithm of equation (i) given : log_(10)k=log_(10)A(E_(a))/(2.3030RT)" ".....(ii) The rate constant for a reaction is . log_(10)"sec"^(-1)=14-(1.25xx10^(4)K)/(T) " ".....(iii) The intercept of the plot oc log_(10)k agianst 1/T is equal to:

The rate of chemical reaction are strongly affected by temperature . Arrhenius (1889) gave following relation between rate contant and temperature . k=Ae^(-E_(a)//RT)" ".....(i) This equation is called Arrhenius equation. The constant 'A' is caleld Arrhenius of pre-exponential factor. Logarithm of equation (i) given : log_(10)k=log_(10)A(E_(a))/(2.3030RT)" ".....(ii) The rate constant for a reaction is . log_(10)"sec"^(-1)=14-(1.25xx10^(4)K)/(T) " ".....(iii) Energy of activation in K cal "mol"^(-1) is:

Assertion (A) : k=Ae^(-E_(a)//RT) , the Arrhenius equation represents the dependence of rate constant with temperature. Reason (R ): Plot of log.k against 1//T is linear and the activation energy can be calculated with this plot.

In Arrhenius equation , K=Ae^(-E_a//RT) . The A is

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