Observe the graph in the diagram and answer the following questions :
(i) If slope is equal to `-2.0xx10^(6)sec^(-1)`, what will be the value of rate constant ?
(ii) How does the half-life of zero order reaction relate to its rate constant ?

Explanation

(i) For a 1st order reaction
`k=(2.303)/(t)log""([R]_(0))/([R])" or "(kt)/(2.303)=log[R]_(0)-log[R]" or "log[R]=-(k)/(2.303)t+log[R]_(0)`
`:." Plot of log [R] vs t is linear with slope "=-(k)/(2.303)`
`:.-(k)/(2.303)=-2xx10^(6)s^(-1)" or "k=4.606xx10^(-6)s^(-1)`
(ii) For a zero order reaction `t_(1//2)=([A]_(0))/(2k)`