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The activation energy for the reaction, ...

The activation energy for the reaction, `2Hi(g) to H_(2)(g) + I_(2)(g)` is 209.5 kJ `moli^(-1)` at 581 K. Calculate the fraction of molecules of reactants having energy equal to or greater than activation energy.

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Fraction of molecules having energy equal to or greater than activation energy `=x=(n)/(N)=e^(-E_(a)//RT)`
`:.lnx=-(E_(a))/(RT)" or "logx=-(E_(a))/(2.303"RT")`
or `logx=-(209.5xx10^(3)" J mol"^(-1))/(2.303xx8.314" JK"^(-1)mol^(-1)xx581" K")=-18.8323`
`:.x=" Antilog"(-18.8323)="Antilog "bar(19).1677=1.471xx10^(-19)`
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