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Consider the decomposition of N(2)O(5) a...

Consider the decomposition of `N_(2)O_(5)` as
`N_(2)O_(5)rarr2NO_(2)+1//2O_(2)`
The rate of reaction is given by
`-(d[N_(2)O_(5)])/(dt)=(1)/(2)(d[NO_(2)])/(dt)=2(d[O_(2)])/(dt)`
`=k_(1)[N_(2)O_(5)]`
Therefore `(-d[N_(2)O_(5)])/(dt)=k_(1)[N_(2)O_(5)]`
`(+d[NO_(2)])/(dt)=2k_(1)[N_(2)O_(5)]=k_(1)[N_(2)O_(5)]`
`(+d[O_(2)])/(dt)=(1)/(2)k_(1)[N_(2)O_(5)]=k_(1)[N_(2)O_(5)]`
Choose the correct option

A

`k_(1)=k_(1)'=k_(1)''`

B

`k_(1)=2" k"_(1)'=k_(1)''`

C

`2" k"_(1)=k_(1)'=4" k"_(1)''`

D

`4" k"_(1)=2" k"_(1)'=k_(1)''`

Text Solution

Verified by Experts

The correct Answer is:
C
`-(d[N_(2)O_(5)])/(dt) = (1)/(2)(d[NO_(2)])/(dt) = 2""(d[O_(2)])/(dt)`
`k_(1)[N_(2)O_(5)] = (1)/(2) k_(1)'[N_(2)O_(5)] = 2k_(1)''[N_(2)O_(5)]`
or `k_(1) = (1)/(2)k_(1)' = 2k_(1)'' or 2k_(1) = k_(1)' = 4k_(1)''`
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Consider the decomposition of N_2O_5 as N_2O_5rarr2NO_2+1/2O_2 The rate of reaction is given by (-d[N_2O_5])/(dt)=1/2(d[NO_2])/(dt)=2(d[O_2])/(dt)=k_1[N_2O_5]" Therefore,"(-d[N_2O_5])/(dt)=k_1[N_2O_5] , (+d[NO_2])/(dt)=2k_1[N_2O_5]=k_1^(')[N_2O_5],(d[O_2])/(dt)=1/2k_1[N_2O_5]=k_1^('')[N_2O_5] Choose the correct option.

2N_(2)O_(5)to4NO_(2)+O_(2) . The rate of reaction in terms of N_(2)O_(5) will be

2N_(2)O_(5) rarr 4NO_(2) + O_(2) If (-d[N_(2)O_(5)])/(dt) = k_(1)[N_(2)O_(5)] (d[NO_(2)])/(dt) = k_(2)[N_(2)O_(5)] (d[O_(2)])/(dt) = k_(3)[N_(2)O_(5)] What is the relation between k_(1), k_(2) , and k_(3) ?

For the reaction, N_(2)O_(5) rarr 2NO_(2)+1/2O_(2), Given -(d[N_(2)O_(5)])/(dt)=K_(1)[NO_(2)O_(5)] (d[NO_(2)])/(dt)=K_(2)[N_(2)O_(5)] and (d[O_(2)])/(dt)=K_(3)[N_(2)O_(5)] The relation in between K_(1), K_(2) and K_(3) is:

The rate of reaction. 2N_(2)O_(5) to 4NO_(2) + O_(2) can be written in three ways. (-d[N_(2)O_(5)])/(dt) = k[N_(2)O_(5)] (d[N_(2)O_(5)])/(dt) =( k^(')[N_(2)O_(5)]) (d[O_(2)])/(dt) = (k^(')[N_(2)O_(5)]) The relation between k and k^(') are:

For the reaction, 2NO_(2)rightarrow2NO+O_(2) ,rate is expressed as : (a) -(1)/(2)(d[NO_(2)])/(dt)=(1)/(2)(d[NO])/(dt)=(d[O_(2)])/(dt) (b) -(1)/(2)(d[NO_(2)])/(dt)=-(1)/(2)(d[NO])/(dt)=(d[O_(2)])/(dt) (c) -(2d[NO_(2)])/(dt)=(2d[NO])/(dt)=(d[O_(2)])/(dt) (d) -(d[NO_(2)])/(dt)=(d[NO])/(dt)=(d[O_(2)])/(dt)

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