The rate of the reaction `A rarr` products, at the initial concentration of `3.24 xx 10^(-2)M` is nine times its rate at another initial concentration of `1.2 xx 10^(-3)M`. The order of reaction is

Options

A. `(1)/(2)`
B. `(3)/(4)`
C. `(3)/(2)`
D. `(2)/(3)`

Answer

D

Explanation

`9 r = k(3*24 xx 10^(-2))^(n)" "…(i)`
`r = k(1* 2 xx 10^(-3))^(n)" "…(ii)`
Dividing (i) by (ii),
` 9 = ((3.24 xx 10^(-2))/(1*2 xx 10^(-3)))^(n) or 9 = (27)^(n)`
or `(3)^(2) = (3^(3))^(n) = (3)^(3n).`
Hence, `3 n = 2 or n = 2//3`.