The time for half life period of a certain reaction `A to ` Products is 1 hour. When the initial concentration of the reactant 'A', is `2.0" mol L"^(-1)`, how much time does it take for its concentration to come from `0.50" to "0.25" mol L"^(-1)`, how much time does it take for its concentration to come from `0.50" to "0.25" mol L"^(-1)` if it is a zero order reaction ?

Options

A. 0.25 h
B. 1 h
C. 4 h
D. 0.5 h

Answer

A

Explanation

For a zero order reaction,
`k = ([A]_(0))/(2t_(1//2)) = (2*0 mol L^(-1))/(2 xx 1 hr) = 1.0 mol L^(-1)hr^(-1)`
` t= (1)/(k) {[A_(0)]-[A]} = (1)/(1*0) (0.50 - 0.25) = 0.25` hr