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The rate constant of a second order reac...

The rate constant of a second order reactions
`2A rarr` Products, is `10^(-4) "lit mol"^(-1) "min"^(-1)`. The initial concentration of the reactant is `10^(-2) "mol lit"^(-1)`. What is the half life (in min) ?

A

10

B

1000

C

100

D

`10^(6)`

Text Solution

Verified by Experts

The correct Answer is:
D
Half -life period of a second order reaction
`t_(1//2) = (1)/("Rate constant" xx "Initial conc.") = (1)/(ka)`
`=(1)/(10^(-4) L mol^(-1) min^(-1) xx 10^(-2) mol L^(-1))`
` = 10^(6) min`
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