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For a reation: A rarr Product, rate la...

For a reation: `A rarr` Product,
rate law is `-(d[A])/(dt)=K[A]_(0)`.
The concentration of `A` left after time `t` when `t=1/K` is:

A

`([A]_(0))/(e)`

B

`[A]_(0)xxe`

C

`([A]_(0))/(e^(2))`

D

`(1)/([A]_(0))`

Text Solution

Verified by Experts

The correct Answer is:
A
The given rate law shows that it is a reaction of 1st order. For 1st order reacion, `[A] = [A]_(0) e^(-kt)`
When `t = (1)/(k), [A] = [A]_(0)e ""^(-k(1)/(2))[A]_(0)e^(-1)=([A]_(0))/(e)`
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