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For the first-order reaction T(av) (aver...

For the first-order reaction `T_(av)` (average life), `T_(50)` and `T_(75)` in the increasing order are :

A

`t_(50)lt t_(av) lt t_(75),`

B

`t_(50)lt t_(75) lt t_(av),`

C

`t_(av)lt t_(50) lt t_(75),`

D

`t_(av)=t_(50) lt t_(75),`

Text Solution

Verified by Experts

The correct Answer is:
A

`t_(av) = (1)/(k) = (1)/(0*693//t_(1//2)) = (t_(1//2))/(0*693) = 1*44 t_(50%)`
Also, we know that `t_(75%) = 2 xx t_(50%)`
Hence, `t_(50%) lt t_(av) lt t_(75%)`
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