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The formation of H(2)O(2) in the upper a...

The formation of `H_(2)O_(2)` in the upper atmosphere follows the mechanism
`H_(2)O+Orarr2OH rarrH_(2)O_(2)`
`DeltaH=72 " kJ" " mol"^(-1), E_(a)=77 " kJ mol"^(-1)`
`E_(a)` for the backward process is

A

`5" kJ mol"^(-1)`

B

`-5" kJ mol"^(-1)`

C

`149" kJ mol"^(-1)`

D

`-149" kJ mol"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
Activation energy for bhackward reaction `=77-72=5 " kJ mol"^-1`.
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There is formation of H_(2)O_(2) in the upper atomsphere. H_(2)O + O rarr 2OH rarr H_(2)O_(2) Delta H = 72 kJ mol^(-1) , E_(a) = 77 kJ mol^(-1) What will be the E_(a) for bimolecular recombination of two OH radicals to form H_(2)O and O in kJ.

In gaseous reaction, important for the understanding of the upper atmosphere H_(2)O and O react bimolecularly to from two OH readicals. DeltaH for this reaction is 72 kJ at 500 K and E_(a) is 77 kJ "mol"^(-1) , then E_(a) for the bimolecular recombination of two OH readicals to form H_(2)O and O is :

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Calculate the standard enthalpy of formation of CH_(3)OH(l) from the following data: CH_(3)OH(l)+3/2O_(2)(g) rarr CO_(2)(g)+2H_(2)O(l), …(i), Delta_(r)H_(1)^(Θ)=-726 kJ mol^(-1) C(g)+O_(2)(g) rarr CO_(2)(g), …(ii), Delta_(c )H_(2)^(Θ)=-393 kJ mol^(-1) H_(2)(g)+1/2O_(2)(g) rarr H_(2)O(l), ...(iii), Delta_(f)H_(3)^(Θ)=-286 kJ mol^(-1)

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