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Starting with an initial pressure of 5 a...

Starting with an initial pressure of 5 atm of azoisopropane, `40%` of it decomposes into nitrogen and hexane vapours in one hour. The pressure in atm exerted by the mixture in atm at this time will be

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The correct Answer is:
7
`(CH_3)_2CHN=NCH(CH_3)_2(g)underset(N_2(g)+C_6H_14(g))(to)`
Initial pressure 5 atm 0 0
After 1 hour
`5-40/100xx5" 2atm 2atm"`
`=5-2" atm "=3 " atm"`
Total pressure after one hour = 3 + 2 + 2 = 7 atm.
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