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Assertion: 50% of reaction is completed ...

Assertion: `50%` of reaction is completed in `50 sec`, therefore, `75%` of the reaction will be completed in `75 sec`.
Reason: The rate constant of a zero order reaction depends uopn time as `k = (1)/(t){[A]_(0) - [A]}`.

A

Statement-1 is True, Statement-2 is True , Statement-1 is a correct explanation of Statement-1.

B

Statement-1 is True, Statement-2 is True , Statement-2 is NOT the correct explanation of Statement-1.

C

Statement-1 is True, Statement-2 is False.

D

Statement-1 is False, Statement-2 is True.

Text Solution

Verified by Experts

The correct Answer is:
C

Correct Statement-2. Rate constant of any reaction is constant at constant temperature and does not change with time or concentration. However, statement-1 is correct because
`t=(1)/(k){[A]_(0)-[A]}`
For `50%,t_(50%)=(1)/(k){[A]_(0)-([A]_(0))/(2)}=([A]_(0))/(2k)=50" sec"`
For `75%,t_(75%)=(1)/(k){[A]_(0)-([A]_(0))/(4)}`
`=([A]_(0))/(k)xx(3)/(4)=([A]_(0))/(2k)xx(3)/(2)=75" sec"`
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