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The rate constant for the reaction COCl(...

The rate constant for the reaction `COCl_(2)(g)toCO(g)+Cl_(2)(g)` is given by
ln `[k//min^(-1)]=-11067//"TK"+31.33`
Calculate the temperature at which the rate of this reaction will be doubled from that at `25^(@)C.`

Text Solution

Verified by Experts

`T_(1)=25^(@)C=298" K, ""Rate constant = k"`
`T_(2)=?," Rate constant "=2" k"`
`"ln "k=-(11067)/(298)+31.33`
`"ln "2" k"=-(11067)/(T_(2))+31.33`
`:." ln "2k-" ln "k=-11067((1)/(T_(2))-(1)/(298))" or ""ln "2=-11067((1)/(T_(2))-(1)/(298))`
or `log2=(-11063)/(2.303)((1)/(T_(2))-(1)/(298))" or "0.3010xx(2.303)/(11063)=(1)/(298)-(1)/(T_(2))`
or `" "(1)/(T_(2))=(1)/(298)-0.0000627=0.00336-0.00006=0.0033`
or `" "T_(2)=(1)/(0.0033)=303" K"=(303-273)^(@)C=30^(@)C`
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