The coagulation of 200 mL of a positive sol took place when 0.73 g HCl was added to it without changing the volume much. The flocculation value of HCl for the colloid is :

Options

A. `0.365`
B. `36.5`
C. `100`
D. `1.50`

Answer

C

Explanation

200 mL of the sol required `=0.73 ` g HCl
`=(0.73)/(36.5)mol =0.02mol =20` mmol.
`therefore100 mL` (1L) of the sol will require
`=(20)/(200)xx1000=100` mmol.