What happens to the colour of coordination compound `[Ti(H_(2)O)_(6)]Cl_(3)` when heated gradually ?

Explanation

To determine what happens to the color of the coordination compound \([Ti(H_2O)_6]Cl_3\) when heated gradually, we can follow these steps:

### Step 1: Identify the Oxidation State
The first step is to find the oxidation state of titanium in the complex \([Ti(H_2O)_6]Cl_3\). The complex is neutral, and the chlorides are anions with a charge of -1. Since there are three chloride ions, the total negative charge is -3. Therefore, the oxidation state of titanium (Ti) can be calculated as follows:

\[ \text{Let the oxidation state of Ti be } x. \]
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