Write the `IUPAC` nomenclature of the given complex along with its hybridisation and structure
`K_(2)[Cr(NO)(NH_(3))(CN)_(4)],mu =1.73.BM` .

Explanation

`mu =sqrt(n(n+2))=1.73` which gives n = 1
This means that chromium ion has one unpaired electrons, i.e., it is present as `Cr^(+)` or Cr (I). This implies that NO is present as nitrosonium ion. Hence, the name will be potassium amminetetracyanonitrosonium chromate (I)

In the complex, as there is only one unpaired electron and coordination number is 6, it will become

i.e., it will undergo `d^(2)sp^(3)` hybridisation to give octahedral geometry.