In the pair, `(CH_(3))_(3)C Cl and CH_(3)Cl, CH_(3)Cl` will react faster in `S_(N)2` reaction with `OH^(-)`. Explain.

Explanation

To determine which compound reacts faster in an \( S_N2 \) reaction with \( OH^- \), we need to analyze the two compounds: \( (CH_3)_3CCl \) (tert-butyl chloride) and \( CH_3Cl \) (methyl chloride).

### Step-by-Step Solution:

1. **Identify the Structure of Each Compound**:
- \( (CH_3)_3CCl \) is a tertiary alkyl halide, where the carbon attached to chlorine is bonded to three other carbon atoms.
- \( CH_3Cl \) is a primary alkyl halide, where the carbon attached to chlorine is bonded to only one carbon atom.

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