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Out of two bromoderivatives C(6)H(5)CH...

Out of two bromoderivatives
`C_(6)H_(5)CH(CH_(3))Br and C_(6)H_(5)CH(C_(6)H_(5))Br`, which one is more reactive in `S_(N^(1))` reaction and why?

Text Solution

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In `S_(N)1` reaction, reactivity depends upon the stability of the intermediate carbocation. Thus,

The carbocation (II) derived from `C_(6)H_(5)CH(C_(6)H_(5))Br` is stabilized by +R-effect of the two `C_(6)H_(5)` groups the carbocation (I) derived from `C_(6)H_(5)CH(CH_(3))Br` is stabilized by +R-effect of one `C_(6)H_(5)` group and +I-effect of the `CH_(3)` group. since +R-effect is much stronger than +I-effect, therefore, carbocation (II) is more stable than carbocation (I). thus, `C_(6)H_(5)CH(C_(6)H_(5))Br` is more reactive than `C_(6)H_(5)CH(C_(6)H_(5))Br` is more reactive than `C_(6)H_(5)CH(CH_(3))Br` in `S_(N)1` substitution reaction.
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Answer the following: (i) Haloalkanes easily dissolve in organic solvents, why? (ii) What is known as a racemic mixture ? Give an example. (iii) Of the two bromoderivatives, C_6H_5CH (CH_3) Br and C_6H_5CH (C_6H_5)Br , which one is more reactive in S_(n^1) substitution reaction and why?

C_(6)H_(5)CH=CH-CO-C_(6)H_(5)

C_(6)H_(5)-CH=CH-CO-CH_(3)

The correct order of reactivity of the compounds (I) C_(6)H_(5)H_(2)(Br) , (II) C_(6)H_(5)CH(C_(6)H_(5))Br , (III) C_(6)H_(5)CH(CH_(3))Br , (IV) C_(6)H_(5)C(CH_(3))(C_(6)H_(5))Br in the increasing order of reactivity in S_(N^(2)) reactions is

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  13. What do prefixes (+),(-) and (+-) before an organic compound mean?

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