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CH(3)Br+Nu^(-)rarrCH(3)Nu+Br^(-) The d...

`CH_(3)Br+Nu^(-)rarrCH_(3)Nu+Br^(-)`
The decreasing order of the rate of the above reaction with nucleophiles `(Nu^(-))` A to D is :
`[Nu^(-)=(A)PhO^(-),(B)AcO^(-),(C)HO^(-),(D)CH_(3)O^(-)]`

A

DgtCgtAgtB

B

DgtCgtBgtA

C

AgtBgtCgtD

D

BgtDgtCgtA

Text Solution

Verified by Experts

The correct Answer is:
A
Phenoxide ion is less resonance stabilized than `AcO^(-)` ion, therefore, nucleophilicity decreases in the order:
`CH_(3)O^(-)(D) gt HO^(-)(C) gt PhO^(-)(A)AcO^(-)(B)` thus, option (a) is correct.
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