The major product formed in the reaction is:
`CH_(3)-underset(H)underset(|)overset(CH_(3))overset(|)(C)-CH_(2)Brunderset(CH_(3)OH)overset(CH_(3)O^(Ө))to`

Options

A. `CH_(3)-underset(H)underset(|)overset(CH_(3))overset(|)(C)-CH_(2)OCH_(3)`
B. `CH_(3)-underset(OCH_(3))underset(|)(C)H-CH_(2)CH_(3)`
C. `CH_(3)-overset(CH_(3))overset(|)(C)=CH_(2)`
D. `CH_(3)-underset(OCH_(3))underset(|)overset(CH_(3))overset(|)(C)-CH_(3)`

Answer

C

Explanation

Since `CH_(3)O^(-)` is a strong nucleophile as well as a strong base, therefore, it can either bring about substitution or elimination. Now, the `CH_(3)` group at `beta`-carbon causes steric hindrance to nucleophiolic substitution `(S_(N)2)`, therefore, elimination `(E_(2))` occurs preferentially to form 2-methylpropene