In a mixture, two enantiomers are found to be present in 85% and 15% respectively. The enatiomeric excess (e,e) is

Options

A. 0.85
B. 0.15
C. 0.7
D. 0.6

Explanation

To find the enantiomeric excess (ee) in a mixture of two enantiomers, we can follow these steps:

### Step 1: Understand the Composition of the Mixture
We have two enantiomers in the mixture:
- Enantiomer 1: 85%
- Enantiomer 2: 15%

### Step 2: Calculate the Enantiomeric Excess (ee)
The enantiomeric excess is calculated using the formula:
\[ \text{Enantiomeric Excess (ee)} = \left| \text{Percentage of one enantiomer} - \text{Percentage of the other enantiomer} \right| \]

### Step 3: Substitute the Values
Substituting the values from the mixture:
\[ \text{ee} = |85\% - 15\%| \]

### Step 4: Perform the Calculation
Now, calculate the difference:
\[ \text{ee} = |85 - 15| = |70| = 70\% \]

### Conclusion
Thus, the enantiomeric excess (ee) in the mixture is **70%**.

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