How many moles of methane are required to produce `22 g CO_(2)` (g) after combustion?

Explanation

The balanced chemical equation for the combustion of methane is :
`underset("1 mole")(CH_(4))+2O_(2)rarr underset(=12+2xx16=44g)underset("1 mole")(CO_(2))+2H_(2)O`
Thus, to produce 44 g `CO_(2), CH_(4)` required = 1 mole
`therefore" To produce 22 g of "CO_(2),CH_(4)` required `=(1)/(44)xx22"mole"="0.5 mole"`