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The weight of a molecule of the compound...

The weight of a molecule of the compound`C_(60)H_(122)` is

A

`1.4xx10^(-21)g`

B

`1.09xx10^(-21)g`

C

`5.025xx10^(23)g`

D

`16.023xx10^(23)g`

Text Solution

Verified by Experts

The correct Answer is:
A
1 mole of `C_(60)H_(122)=60xx12+122xx1g=842 g`
`=6.023xx10^(23)` molecules
Weighta of 1 molecule = `842/(6.023xx10^(23))g`
`=139.8xx10^(-23)=1.398xx10^(-21)=1.4xx10^(-21)g`
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