The total number of electrons in 18 mL of water `("density = 1 g "mL^(-)1)` is

Options

A. `6.02xx10^(23)`
B. `6.02xx10^(25)`
C. `6.02xx10^(24)`
D. `6.02xx18xx10^(23)`

Answer

C

Explanation

`"18 mL of "H_(2)O=18" g of "H_(2)O="1 mole of "H_(2)O`
`=6.02xx10^(23)" molecules"`
Electrons present in 1 molecule of `H_(2)O`
`2xx1+8=10`
`therefore" Electrons present in "6.02xx10^(23)` molecules
`=10xx6.023xx10^(23)=6.02xx10^(24)`