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A gas mixture contains 50% helium and 50...

A gas mixture contains `50%` helium and `50%` methane by volume. What is the percent by weight of methane in the mixture.

A

`19.97%`

B

`20.05%`

C

`50%`

D

`80.03%`

Text Solution

Verified by Experts

The correct Answer is:
D
Equal volumes contain equal number of moles.
Hence, molar ratio of `He:CH_(4)=1:1`
`therefore" Ratio by weight "=4:16=1:4`
`therefore CH_(4)` present by weight `=(4)/(5)xx100=80%`
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