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Number of mole of 1 m^(3) gas at NTP are...

Number of mole of `1 m^(3)` gas at `NTP` are:

A

`4.46`

B

`44.6`

C

446

D

4460

Text Solution

Verified by Experts

The correct Answer is:
B
`1m^(3)=10^(3)L=1000L`
`"1 mole = 22.4 L"`
`therefore" Moles present in 1000 L"=(1000)/(22.4)=44.6`
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