0.3 g of an acid is neutralized by `40 cm^(3)` of 0.125 N NaOH. Equivalent mass of the acid is

Options

A. 60
B. 45
C. 30
D. 63

Answer

A

Explanation

`40cm^(3)` of 0.125 N NaOH neutralise acid = 0.3 g
`therefore 1000cm^(3)` of 1 N NaOH will neutralise acid
`=(0.3)/(40)xx(1000)/(0.125)g=60g`
`1000cm^(3)` of 1 N NaOH contain one g ram equivalent of NaOH. It will neutralise one gram equivalent of the acid.
Hence, equivalent weight of acid = 60