The number of molecules in 100 mL of `0.02N` `H_(2)SO_(4)` is:

Options

A. `6.02xx10^(22)`
B. `6.0xx10^(21)`
C. `6.02xx10^(20)`
D. `6.02xx10^(18)`

Answer

C

Explanation

`0.02N H_(2)SO_(4)=0.01M H_(2)SO_(4)`
1000 mL of `0.01 M H_(2)SO_(4)` contains `H_(2)SO_(4)`
`="0.01 mole"`
`therefore 100mL" of "0.01M H_(2)SO_(4)" contains "H_(2)SO_(4)`
`=0.001" mole"=10^(-3)"mole"`
`"Molecules present"=10^(-3)xx6.02xx10^(23)`
`=6.02xx10^(20)`