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A 100 ml solution of 0.1N-HCl was titrat...

A 100 ml solution of 0.1N-HCl was titrated with 0.2 N-NaOH solution. The titration was discontinued after adding 30 ml of NaOH solution. The remaining titration was completed by adding 0.25N-KOH solution. The volume of KOH required for completing the titration is

A

70 ml

B

32 ml

C

35 ml

D

16 ml

Text Solution

Verified by Experts

The correct Answer is:
D
`N_(1)V_(1)=N_(2)V_(2)+N_(3)V_(3)`
i.e., `0.1xx100=0.2xx30+0.25V_(3)`
`"or "0.25V_(3)=4 or V_(3)=16ml`
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