The ratio of masses of oxygen and nitrogen in a particular gaseous mixture `1:4`. The ratio of number of their molecule is :

Options

A. `3:16`
B. `1:4`
C. `7:32`
D. `1:8`

Answer

C

Explanation

Suppose the mass of `O_(2)` in the mixture = x g
Then, mass of `N_(2)` in the mixture = 4 x g
No. of moles of `O_(2)=(x)/(32)`
No. of moles of `N_(2)=(4x)/(28)`
As molecules are in the ratio of their moles, ratio of their molecules is
`O_(2):N_(2)=(x)/(32):(4x)/(28)=(1)/(32):(1)/(7)=7:32`