Percentage of Se in peroxidase anhydrase enzyme is `0.5%` by weight (at. Wt. `=78.4)`, then minimum molecular weight of peroxidase anhydrase enzyme is:

Options

A. `1.568xx10^(4)`
B. `1.568xx10^(3)`
C. `15.68`
D. `3.136xx10^(4)`

Answer

A

Explanation

`0.5%` by weight means 0.5 g Se is present in 100 g of peroxidase anhydrous enzyme. As at least one atom of Se must be present in the enzyme and atomic weight of Se = 78.4, therefore, 1 g atom of Se, i.e., 78.4 g will be present in enzyme
`=(100)/(0.5)xx78.4g=1.568xx10^(4)g`