In Haber process 30 litre of dihydrogen and 30 litres of dinitrogen were taken for reaction which yielded only`50%` of the expected product. What will be the composition of gaseous mixture under the aforesaid condition in the end ?

Options

A. 20 litres `NH_(3)`, 25 litres `N_(2)`, 20 litres `H_(2)`
B. 10 litres `NH_(3)`, 25 litres `N_(2)`, 15 litres `H_(2)`
C. 20 litres `NH_(3)`, 10 litres `N_(2),` 30 litres `H_(2)`
D. 20 litres `NH_(3)`, 25 litres `N_(2)`, 15 lites `H_(2)`

Answer

B

Explanation

`N_(2)(g)+3H_(2)(g)hArr 2NH_(3)(g)`
1 L of `N_(2)` reacts with 3 L of `H_(2)` to form 2 L of `NH_(3)`.
Thus, `N_(2)` is the limiting reactant.
10 L `N_(2)` will react with 30 L `H_(2)` to form 20 L `NH_(3).`
As actual yield is `50%` of hte expected value, `NH_(3)` formed = 10 L, `N_(2)` reacted = 5 L,
`H_(2)` reacted = 15 L
`therefore" Mixture will contain 10 L NH"_(3),25 L N_2),`
`15L H_(2)`.