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For the formation of 3.65 g of hydrogen ...

For the formation of 3.65 g of hydrogen chloride gas, what volumes of hydrogen gas and chlorine gas are required at NTP conditions?

A

1.12 lit, 1.12 lit

B

1.12 lit, 2.24 lit

C

3.65 lit, 1.83 lit.

D

1 lit., 1 lit.

Text Solution

Verified by Experts

The correct Answer is:
A

`{:(H_(2)(g),+,Cl_(2)(g),rarr,2HCl(g)),("1 mole",,"1 mole",,"1 mole"),("22.4 L",,"22.4 L",,2xx36.5g):}`
`therefore" For formation of 3.65 g HCl, "H_(2) or Cl_(2)" required"`
`=(22.4)/(2xx36.5)xx3.65L=1.12L`
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