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The number of Cl^(-) ions in 100 mL of ...

The number of `Cl^(-)` ions in 100 mL of 0.001 M HCl solution is

A

`6.022xx10%(23)`

B

`6.022xx10^(20)`

C

`6.022xx10^(19)`

D

`6.022xx10^(24)`

Text Solution

Verified by Experts

The correct Answer is:
C
1 L or 1000 mL of 0.001 M HCl solution contains
`Cl^(-)=0.0001` mole
`therefore" 100 mL of 0.001 M HCl will contain Cl"^(-1)" ions"`
`=(0.001)/(1000)xx100=10^(-4)" mole"`
`=10^(-4)xx(6.022xx10^(23))`
`=6.022xx10^(19)`
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