How many moles of lead (II) chloride will be formed from a reaction between 6.5 g of PbO and 3.2 g of HCl?

Options

A. 0.044
B. 0.333
C. 0.011
D. 0.029

Answer

D

Explanation

`PbO+2HCl rarr PbCl_(2)+H_(2)O`
Molar mass of PbO `=207+16=223" g mol"^(-1)`
`therefore" 6.5 g PbO"=(6.5)/(223)" mole"=0.029" mole"`
Molar mass of HCl = 36.5 g `mol^(-1)`
`therefore" 3.2 g HCl"=(3.2)/(36.5)" mole = 0.0877 mole"`
1 mole of PbO reacts with 2 moles of HCl
Thus, PbO is the limiting reactant.
1 mole of PbO produces 1 mole of `PbCl_(2)`
`therefore 0.029` mole of PbO will produce `PbCl_(2)`
= 0.029 mole.